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...Alaa Saad 12/12/15 PH2530 Exercise 1.1 1. The turning radius of a car is 36 ft. What will be the distance in meters? 10.97 meters 2. What is the sum of 1370 cm, 1575 mm, and 8.63 m in meters? 23.91 meters 3. The cross-sectional area of a hole is 725 cm2. Given that the area of a circle is A = πr2, find the radius of the hole. 15.19 cm 4. what will be the value of x? x=+ or – (sqrt 3-8y)/2 sqrt y 5. Milwaukee is 121 mi (air miles) due west of Grand Rapids. Maria drives 255 mi in 4.75 h from Grand Rapids to Milwaukee around Lake Michigan. Find: a. Her average driving speed = 47.37 mph b. Her average travel velocity = 76.21 kh/h 6. A rock is thrown down with an initial speed of 10.0 m/s from a bridge in the water. It takes 2.75 s for the rock to hit the water. a. Find the speed of the rock as it hits the water = 36.99 m/s b. How high is the bridge above the water? = 101.7 meters or 333.7 ft 7. What are the characteristics of an object in a state of free fall with respect to its speed and acceleration? Objects in freefall accelerate at 32.2 ft/s squared or at a constant acceleration. 8. An archer needs to hit a bull’s eye on a target at eye level of 60.0 ft away. If the archer fires the arrow from the eye level with a speed of 47.0 ft/s at an angle of 25.0 degrees above the horizontal, will the arrow hit the target? No 9. What is inertia? Discuss which object among the following sets has more inertia and why: a. A more massive object or a less massive......

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...Physics. PH2530 Exercise1.1 Gus Perez 1.-The turning radius of a car is 36 ft. What will be the distance in meters? We got 1ft = 0.3048 m. So we solve it like, Distance = 36 ft. x (0.3048 m. / 1 ft.) = 10.9728 m. is the answer. 2. What is the sum of 1370 cm, 1575 mm, and 8.63 m in meters? (Hint: Refer to section 1.9 in the textbook.). We convert everything to meters. We know that 1m = 100 cm and 1cm = 10 mm. so we got, 1370 cm = 13.7 m and 1575mm = 1.575 m, so we add up the 3 values; Distance = 13.7 + 1.575 + 8.63 = 23.905 m. 3. The cross-sectional area of a hole is 725 cm2. Given that the area of a circle is A = πr2, find the radius of the hole. (Hint: Use the problem-solving method described in section 2.3 of the textbook.). When solving for the radius r, we get; r=A√π We got A=725 and π=3.1416. So the answer is r = 15.19cm. 4. If 4y = (3) / (x² + 2), what will be the value x? For this problem, we solve for x from the equation. x² + 2 = 3 / 4y x² = (3/4y) - 2 and the value for x is the square root of (3/4y) - 2; x=√[(34y)-2] 5. Milwaukee is 121 mi (air miles) due west of Grand Rapids. Maria drives 255 mi in 4.75 h from Grand Rapids to Milwaukee around Lake Michigan. Find: Given d = 255 mi and t = 4.75 h. a. Her average driving speed. The average speed is v = d/t = 255mi / 4.75 h = 53.634 mi/h b. Her average travel velocity. Her average velocity is 53.634 mi/h from Grand Rapids to Milwaukee around Lake Michigan. 6. A rock is thrown down with an initial speed of 10.0......

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